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Detail specifications 43SB - Level 3 ★
The Rubensohl convention after a 2♥ overcall on 1NT opening
The Rubensohl is used by the responder after a 1NT opening and an overcall. Kit recommands that experienced players use this system.
After a natural overcall of 2 CO:
After a natural overcall of 2 CO:
- - all the responder's bids in a suit at the two level are natural
- - from 2NT onwards all bids are Texas transfer bids. 2NT is therefore artificial (Texas for clubs)
- - the impossible Texas is a Stayman
- - the double is a takeout. It could be a Stayman with just 8HCP or show a balanced hand of 8HCP or more.
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Problème E9024
X ambigous that here will work as a Stayman
X ambigous that here will work as a Stayman
After a natural overcall of 2 ♥
- The responder's bids
- in a suit at the two level are natural and non forcing. They are limited to a maximum of 7HCP.
- The double is not punitive. It requires at least 7-8HCP and often reveals a hand that would have bid 2NT without the overcall. The double asks the Partner to bid a four or five-card suit or to bid NT if he has stoppers in the overcall suit. With a suitable hand, the opener can also pass and transform the double into a punitive one! With a hand of just 8HCP it can also be used by the responder as a Stayman non game forcing.
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Problème E9029
3 ♦ The rebid by 3 ♦ after responder's double denies 4 cards in ♠ and a ♥ stopper.
3 ♦ The rebid by 3 ♦ after responder's double denies 4 cards in ♠ and a ♥ stopper.
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Problème E9022
2 ♠ that shows 5 cards in ♠ in a weak hand (less than 8HCP). The 3 ♠ bid by Opener is purely compétitive.
2 ♠ that shows 5 cards in ♠ in a weak hand (less than 8HCP). The 3 ♠ bid by Opener is purely compétitive.
The Texas responses
From 2NT onwards all the responses are Texas. The impossible Texas (for the overcall suit) is a Stayman. This forcing bid requires 8HCP and at least one four-card major.
From 2NT onwards all the responses are Texas. The impossible Texas (for the overcall suit) is a Stayman. This forcing bid requires 8HCP and at least one four-card major.
- 1NT - 2 CO- 2NT = Texas for clubs (it guarantees 6 cards)
- 11NT - 2 CO- 3 clubs = Texas for ♦.
- 11NT - 2 CO- 3 diamonds = the impossible Texas. The responder cannot want to play 3 diamonds so it's a game-forcing Stayman.
- 11NT - 2 CO- 3 hearts = Texas for spades
- 11NT - 2 CO- 4 diamonds = a major two-suiter at least 5-5 1NT - 2 diamonds - double = either a weak Stayman, or else a regular hand of 8-9HCP
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Problème E9030
3♣ Texas transfer for♦ Thanks to the Texas transfer, the opener (with the strong hand) will be playing the 3 ♦ contract.
3♣ Texas transfer for♦ Thanks to the Texas transfer, the opener (with the strong hand) will be playing the 3 ♦ contract.
The 3 ♠ rebid by responder
After the 2 ♥ overcall,The Texas transfer for ♠ is 3 ♥. The 3 ♠ bid is natural ; It shows :
The opener will then choose between 3 NT and 4 ♠ !
After the 2 ♥ overcall,The Texas transfer for ♠ is 3 ♥. The 3 ♠ bid is natural ; It shows :
- 5 cards in ♠
- AND a ♥ stopper
The opener will then choose between 3 NT and 4 ♠ !
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Problème 9085
3 ♠ This response is forcing to game and shows at least 9HCP, 5 cards in ♠ and a ♥ stopper. It is up to the opener to choose the best game : Here, South, being fitted choose game at 4 ♠ ..
3 ♠ This response is forcing to game and shows at least 9HCP, 5 cards in ♠ and a ♥ stopper. It is up to the opener to choose the best game : Here, South, being fitted choose game at 4 ♠ ..
FR version
2 ♠ that show 5 cartes in ♠ and a hand with maximum 7HCP. Most of the time, the opener will pass.